. If CD = 4 and the
perimeter of △ABC is 23,
what is the perimeter
of △ABE?

Answer:
31
Step-by-step explanation:
ABC has a perimeter of 23, so
AB + BC + AC = 23
The perimeter of ABE would be the sum of these sides:
AB + BC + CD + DE + AE
We also know:
AE = AC, CD=4 and DE=4 because ACD is congruent to AED
So, AB + BC + CD + DE + AE = AB + BC + 4 + 4+ AC = 23+8 = 31
The perimeter of △ABE from the given diagram is; 31
We are given;
CD = 4
Perimeter of △ABC = 23
Perimeter is sum of the sides of the triangle.
Thus;
AB + AC + BC = 23
Now, similarly, perimeter of △ABE is;
P = AB + BC + CD + DE + AE
Now, we can observe that;
△ACD is congruent to △AED based on SAS congruency theorem.
Thus;
AE = AC
CD = DE = 4
Thus;
P = AB + BC + CD + DE + AE
>> P = AB + AC + BC + CD + DE
Thus;
P = 23 + 4 + 4
P = 31
Read more on congruency theorems at;https://brainly.com/question/17239468