Answer :
The horizontal velocity of the shadow is -0.33 m/s
The given parameters;
- initial velocity of the fly, V₀ = 0.36 m/s
- angle of projection of the fly, θ = 204°
The horizontal velocity of the shadow is relative to the horizontal velocity of the fly.
The horizontal velocity of the shadow is calculated as follows;
Vₓ = V₀Cosθ
Vₓ = (0.36)Cos(204)
Vₓ = (0.36)(-0.9135)
Vₓ = -0.33 m/s
Thus, the horizontal velocity of the shadow is -0.33 m/s
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