Answered

5)
A plane flies with a velocity of 52 m/s east through a 12 m/s cross wind blowing the plane
south. Find the magnitude and direction (relative to due north) of the resultant velocity at
which it travels.

Answer :

Answer:

53 m/s

[103 degrees E of N]

Explanation:

R = sqrt (52)^2 + (12)

R = 53 m/s

Theta = tan^-1(12/52)

Theta = 103 degrees

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answer

12.99 degrees SE

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