Answer:
180 meters
Explanation:
We know initial position and velocity of the dragster are both zero. We only know acceleration (43 m/s^2) and need to find out how far the dragster moves after 2.9 seconds.
x initial = 0
velocity initial = 0
t=2.9s
a= 43m/s^2
Plug into
[tex]x_{final} =x_{initial} +v_{initial}t+\frac{1}{2} at^2[/tex]
[tex]x_{final} =0} +0t+\frac{1}{2} (43 m/s^2)(2.9s)^2[/tex]
[tex]x_{final} =\frac{1}{2} (43 m/s^2)(8.41s^2)[/tex]
[tex]x_{final}=180.815m = 180m[/tex]
180 meters or 1.8 x 10^2 meters is the answer accounting for 2 sig figs.
