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please help me with this Pythagoras theorem..
A triangle DEF is right- angled at E, with DE=6.7m and EF=5.5m . find the length of DF. ​

Please Help Me With This Pythagoras Theorem A Triangle DEF Is Right Angled At E With DE67m And EF55m Find The Length Of DF class=

Answer :

EMMASCOSTAR1GO

Answer:

8.7m

Step-by-step explanation:

[6.7]²+5.5}²

=[75.14]

√75.14m

=8.7m

SPAMMINGALLOWEDGO

Step-by-step explanation:

[tex] {(df)}^{2} = {(de)}^{2} + {(ef)}^{2} \\ = {6.7}^{2} + {5.5}^{2} \\ = 44.89 + 30.25 \\ = 75.14 \\ df = \sqrt{75.14} = 8.67m \\ thank \: you[/tex]

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