Answer :
The frictional force on the sofa at the given conditions is 460.4 N.
The given parameters:
- weight of the sofa, W = 60 N
- applied force, F = 480 N
- acceleration of the sofa, a = 3.2 m/s²
The mass of the sofa is calculated as follows;
[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{60}{9.8} \\\\m = 6.122 \ kg[/tex]
The frictional force on the sofa is calculated by taking the net force on the sofa as follows
[tex]\Sigma F = ma\\\\F - F_f = ma\\\\F_f = F - ma\\\\F_f = 480 - (6.122\times 3.2)\\\\F_f = 460.4 \ N[/tex]
Thus, the frictional force on the sofa at the given conditions is 460.4 N.
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Answer:
the friction force on the sofa is 288 N
Explanation: