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A rock is dropped from the top of a 2000-foot building. After 1 second, the rock is traveling 32 feet per second. After 2 seconds, the rock
is traveling 64 feet per second. Let y be the rate of descent and be the number of seconds since the rock was dropped.
a. Write a linear equation that relates time x to rate y. (Hint: Use the ordered pairs (1,32) and (2,64).]
b. Use this equation to determine the rate of travel of the rock 15 seconds after it was droppedwas dropped.
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A Rock Is Dropped From The Top Of A 2000foot Building After 1 Second The Rock Is Traveling 32 Feet Per Second After 2 Seconds The Rock Is Traveling 64 Feet Per class=

Answer :

MUSICLOVER10045GO

Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.

To find the rate of decent you would multiply the rate by time:

The equation is y = 32x

B. Replace x with 15 and solve for y:

Y = 32(15)

Y = 480

The rate of speed is 480 feet per second.

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