Answer:
first box(z ):- 4
2nd box(x) :- 5
3rd box(y) :- 12
Step-by-step explanation:
we can equate the equation on both side of equality and can solve it separately.
[tex] \frac{1}{3} + \frac{1}{12} = \frac{x}{y} [/tex]
[tex] \frac{4 + 1}{12} = \frac{x}{y} \\ \frac{5}{12} = \frac{x}{y} [/tex]
now ,
[tex] \frac{z}{12} + \frac{1}{12} = \frac{x}{y} [/tex]
[tex] \frac{z + 1}{12} = \frac{5}{12} [/tex]
[tex]z + 1 = 5 \\ \\ z = 4[/tex]
