1. A rectangular pyramid is intersected by a plane to create the frustum shown. If the height of the original pyramid is 14 m, what is the volume of the frustum?
10 m
4 m
8 m
6 m
12m

The answer needs the volume of the original pyramid minus the small pyramid cut off.
Volume of pyramid = (area of base x height)/3
(12 x 6 x 14)/3 - (4 x 10 x 6)/3 = 256 m^3

The diagram is completely wrong so this problem is actually impossible to solve!
If you slice horizontally across a rectangular pyramid the ratios of the edges will remain constant.
The two rectangles are not the same shape! 12:6 is not the same ratio as 10:4

If the original pyramid in this question was sliced in half the top rectangle of the frustum would be 6 x 3.
In this diagram the height was reduced from 14m to 8m so the top 6m was removed.
If the base was 12 x 6 the top rectangle should be 6/14 smaller = 5.14m by 2.57m (not 10 x 4)

If you are brave you could point this out to your teacher

AKPOSEVICTORGO AKPOSEVICTORGO · Answer 2

The volume of the frustum that is shown in the diagram is: C. 256 m³.

What is the Volume of Frustum?

The volume of frustum = Volume of the bigger rectangular pyramid - Volume of smaller rectangular pyramid.

Find the volume of the original (bigger) rectangular pyramid:

Volume of rectangular pyramid = 1/3(lwh) = 1/3(12 × 6 × 14)

Volume of rectangular pyramid = 336 m³

Find the volume of the smaller (the top that was removed) rectangular pyramid:

Volume of rectangular pyramid = 1/3(lwh) = 1/3(10 × 4 × 6)

Volume of rectangular pyramid = 80 m³

The volume of frustum = Volume of the bigger rectangular pyramid - Volume of smaller rectangular pyramid = 336 - 80 = 256 m³.

Thus, the volume of the frustum that is shown in the diagram is: C. 256 m³.

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