Answer:
Step-by-step explanation:
A( 3 , 4) & C(5 , 8)
Distance = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]
[tex]AC = \sqrt{(5-3)^{2}+(8-4)^{2}}\\\\=\sqrt{(2)^{2}+(4)^{2}}\\\\=\sqrt{4+16}\\\\=\sqrt{20}\\\\= 4.47 units[/tex]
M is the midpoint of AB
A(3,4) &B(7,4)
[tex]M(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\\\\M(\frac{3+7}{2},\frac{4+4}{2})\\\\M(\frac{10}{2},\frac{8}{2})[/tex]
M(5,4)
