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If the diameter of a hockey rink is 250 ft what is the surface area of the sphere?

Answer :

YOHANNAZENEBE66GO

Answer:

62,500 pi

Step-by-step explanation:

diameter = radius + radius

d = 2r

r = d/2

A = 4pi r^2

= 4 pi (d/2)^2

= 4pi d^2/4

= 4pi* 250^2/4

= 4pi * 62,500/4

= 4pi * 15625

= 62,500 pi

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