Answer:
[tex]-\frac{77}{24}[/tex]
Step-by-step explanation:
1. rewrite the equation in standard form: [tex]4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2[/tex]
2. find (h,k), the vertex. the vertex is [tex]\left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)[/tex]
3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2
4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a distance p from the [tex]\left(-\frac{3}{2},\:-\frac{41}{24}\right)[/tex] y coordinate which is at [tex]-\frac{41}{24}\right)[/tex]. Set up the equation:
[tex]y=-\frac{41}{24}-p[/tex]
5. substitute and solve:
[tex]y=-\frac{41}{24}-\frac{3}{2}[/tex]
[tex]y = -\frac{77}{24}[/tex]
hope this helps, ask me questions if you still don't understand.
