Miguel is trying to find the height of a radio antenna on the roof of a local building. He stands at a horizontal distance of 22 meters from the building. The angle of elevation from his eyes to the roof (point A) is 26 degrees , and the angle of elevation from his eyes to the top of the antenna ( oint B) is 31 degrees If his eyes are 1.53 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.

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OEERIVONAGO OEERIVONAGO · Answer 1

Given the 22 m. horizontal distance and the angles of elevation of 26°

and 31° gives the height of the building as approximately 2.49 meters.

Horizontal distance from the building = 22 m

Angle of elevation to the top of the roof = 26°

Angle of elevation to the top of the antenna = 31°

Height of his eyes from the ground = 1.53 m

Required:

The height of the antenna.

Solution:

In a right triangle, we have relative to an angle of the triangle, we have;

Opposite side = Adjacent side

Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75

Which gives;

Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26

Height of antenna = Height of the building + Height of antenna - Height of the building

Therefore;

Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49

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