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solve the following simultaneous linear equations by the substitution method.
3x + 4y = 1
2x + 3y = 1​

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[tex]\displaystyle\bf \left \{ {{3x+4y=1} \atop {2x+3y=1}} \right. => \left \{ {{x=\frac{1-4y}{3} } \atop {2x+3y=1}} \right. => \\\\\\2\cdot\frac{1-4y}{3} +3y=1\: |\times3\\\\2-8y+9y=3\\\\y+2=3\\\\y=1 \;;\:x=(1-4y):3=-1\\\\\\Answer: (-1;1)[/tex]

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