Answer:
Option A
Step-by-step explanation:
We need to solve out ,
[tex]\implies |5x + 30| = 10x [/tex]
We can write it as ,
[tex]\implies 5x + 30 = \pm 10x [/tex]
On simplyfing further,
[tex]\implies 5x + 30 = 10x \quad or \quad 5x +30=-10x [/tex]
On solving the above equation , we will get ,
[tex]\implies \boxed{ x = 6,-2}[/tex]
Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .
Option A is correct .
