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Triangle ABC has A (-3, 6), B (2, 1), and C (9, 5) at its vertices.
The length of side AB is
A. (50)^1/2
B. (65)^1/2
C. (105)^1/2
D. (145)^1/2
units.
The length of side BC is
(one of the above options)
units.
The length of side AC is
(one of the above options)
units.
A. 55.21
B. 85.16
C. 105.26
D. 114.11

Answer :

XATANAGO

Answer:

AB= A. (50)^1/2

BC= B. (65)^1/2

AC= D. (145)^1/2

<ABC≈ 105

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