The length and density of the aluminum cube is 15.46 cm and 1,081.1 kg/m³ respectively
The volume of the aluminum is equal to the weight of the kerosene displaced.
V = 0.05 kg / 13.5 kg/m³
V = 3.7 x 10⁻³ m³
density = mass/volume
density = 4 kg / 3.7 x 10⁻³ m³
density = 1,081.1 kg/m³
V = L³
L = ∛V
L = ∛(3.7 x 10⁻³)
L = 0.1546 m
L = 15.46 cm
Thus, the length and density of the aluminum cube is 15.46 cm and 1,081.1 kg/m³ respectively.
Learn more about density here: https://brainly.com/question/6838128
#SPJ1
