Graph the image of T(

10,

7) after a rotation 270° counterclockwise around the origin.


Answer :

Answer:

[tex]T' = (-7,10)[/tex]

Step-by-step explanation:

Given

[tex]T = (10,7)[/tex]

[tex]r = 270^o[/tex] counterclockwise

Required

Graph of T'

The rule to this is:

[tex](x,y) \to (-y,x)[/tex]

So, we have:

[tex]T(10,7) \to T' (-7,10)[/tex]

Hence:

[tex]T' = (-7,10)[/tex]

See attachment for graph

View image MRROYAL