find the value of x.

Answer:
x = sqrt(33)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
4^2 + x^2 = 7^2
16 + x^2 = 49
Subtract 16 from each side
x^2 = 49-16
x^2 = 33
Take the square root of each side
sqrt(x^2) = sqrt(33)
x = sqrt(33)
[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{c}^{2} = {a}^{2} + {b}^{2} }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt{\color{black}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {7}^{2} - {4}^{2} \: \: } }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {49} - {16} \: \: } }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt \color{black}{{x} = \sqrt{ 33} }}[/tex]
[tex]\quad\quad\quad \boxed{ \tt \color{green}{{x} = \sqrt{ 33} }}[/tex]
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