Answer :
Answer:
a. 0.0535 = 5.35% probability that it will not be discovered
b. 0.9465 = 94.65% probability that it will be discovered
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
a. If it has an emergency locator, what is the probability that it will not be discovered?
Event A: Has an emergency locator.
Event B: Not discovered.
Probability of having an emergency locator:
67% of 76%(discovered).
100 - 88 = 12% of 100 - 76 = 24%(not discovered). So
[tex]P(A) = 0.67*0.76 + 0.12*0.24 = 0.538[/tex]
Probability of having an emergency locator and not being discovered:
12% of 24%. So
[tex]P(A \cap B) = 0.12*0.24[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.12*0.24}{0.538} = 0.0535[/tex]
0.0535 = 5.35% probability that it will not be discovered.
b. If it does not have an emergency locator, what is the probability that it will be discovered?
Event A: Has an emergency locator.
Event B: Discovered.
Probability of having an emergency locator:
67% of 76%(discovered).
100 - 88 = 12% of 100 - 76 = 24%(not discovered). So
[tex]P(A) = 0.67*0.76 + 0.12*0.24 = 0.538[/tex]
Probability of having an emergency locator not being discovered:
67% of 76%. So
[tex]P(A \cap B) = 0.67*0.76[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.67*0.76}{0.538} = 0.9465[/tex]
0.9465 = 94.65% probability that it will be discovered