A cylinder-shaped drainage pipe 66 in. long measures 25.12 in. around.


What is the volume of the drainage pipe?


Answer :

Answer:

Step-by-step explanation:

25.12 inches around means diameter. So radius = 12.56 inches

   volume  [tex]= \pi r^2 \times h =\pi \times 12.56^2 \times 66 = 32709.44 \ in^3[/tex]

Answer:

The volume of the drained pipe is 32692.11 in ³.

Step-by-step explanation:

Given :-

Diameter of drainage pipe = 25.12 in

So, radius , r = 25.12 in = 12.56 in

Height of drainage pipe, h = 66 in.

To Find :-

Volume of the drainage pipe

Solution :-

We know that,

Volume of cylinder = π × r ² × h

substitute the values

Volume of pipe = 3.14 × (12.56 in)² × 66 in

simplify

Volume of pipe =3.14 ×157.7536 in² × 66in

multiplying ✖ the values

Volume of the pipe = 32,692.11 in ³

Therefore, the volume of the drained pipe is 32692.11 in ³.