Answer:
The perimeter of the triangle is 28.82
Step-by-step explanation:
Please check the image uploaded for the diagram.
Perimeter = d₁ + d₂ + d₃
[tex]d_1 = \sqrt{(-10-0)^2 + (-4-3)^2} = \sqrt{100+49} =\sqrt{149} = 12.21\\\\d_2 = \sqrt{(-9-0)^2 + (-7-3)^2} = \sqrt{81+100} =\sqrt{181} = 13.45\\\\d_3 = \sqrt{(-10+9)^2 + (-4+7)^2} = \sqrt{1+9} =\sqrt{10} = 3.16\\\\Perimeter = 12.21 + 13.45 + 3.16 = 28.82[/tex]
