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An electron with a charge of -1.6 x 10-19 C experiences a force of 9.2 x 10-15 N. What is the intensity of the electric field?

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Answer:

Explanation:

[tex]E=\frac{q}{F}[/tex] where q is the charge of the electron and F is the electrostatic force. Filling in:

[tex]E=\frac{-1.6*10^{-19}}{9.2*10^{-15}}[/tex] which gives you an electric field magnitude of

E = -1.7 × [tex]10^{-5[/tex] C/N

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