In this picture, m∠XOZ = 70° and m∠YOZ = 37°. If m∠XOY = (5x + 16)°, what is the value of x?

Answer:
x = 3.4
Step-by-step explanation:
You have the value of xoz = 70, yoz = 37 and xoy = 5x+16
Set your formula up as
xoz = yoz + xoy
70 = 37 + 5x + 16
70 - 37 - 16 = 5x
17 = 5x
17 / 5 = x
3.4 = x
[tex]\huge\bold{Given :}[/tex]
m∠XOZ = 70°
m∠YOZ = 37°
m∠XOY = ( 5x + 16 )°
[tex]\huge\bold{To\:find :}[/tex]
The value of x°.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
[tex]{\boxed{\mathcal{\red{The\:value\:of\: x° \:is\:3.4° .\:}}}}[/tex]✅
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\pink{m∠XOZ\:=\:m∠YOZ\:+\:m∠XOY}[/tex]
➪ 70° = 37° + 5x° + 16°
➪ 5x° + 53° = 70°
➪ 5x° = 70° - 53°
➪ 5x° = 17°
➪ x° = [tex] \frac{17° }{5} [/tex]
➪ x° = 3.4°
[tex]\sf\red{Therefore, \:the\: value \:of \:x°\: is \:3.4°.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]
✒ 70° = 37° + 5 x 3.4° + 16°
✒ 70° = 37° + 17° + 16°
✒ 70° = 70°
✒ L. H. S. = R. H. S.
[tex]\boxed{Hence\:verified.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]