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A 1.50 kg ball moving at 4.50 m/s is caught by a 60.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?

Answer :

LUV2TEACHGO

Answer:

Explanation:

The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:

[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:

[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and

6.75 + 0 = 61.5v so

v = .110 m/s in the same direction as the ball

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