Answer:
The tower is approximately 57.34 meters long
Step-by-step explanation:
The given parameters are;
The type of triangle formed by ΔABC = Non-right triangle
The measure of ∠ACB = 55°
The horizontal displacement of the tower, BX = 5 m
The length of BC = 45 m
Therefore, we have;
Triangle ΔABC type = Right triangle
By the tangent to an acute angle, θ, in a right triangle, we have;
[tex]Tan(\theta) = \dfrac{Opposite \, side \ length}{Adjacent\, side \ length}[/tex]
Where θ is the 55°, we have angle, we have;
[tex]Tan(55^{\circ}) = \dfrac{XA}{XC}[/tex]
BC = BX + XC
∴ XC = BC - BX
XC = 45 m - 5 m = 40 m
[tex]\therefore Tan(55^{\circ}) = \dfrac{XA}{40}[/tex]
XA = 40 × tan(55°) ≈ 57.126
The type of triangle formed by ΔABX = Right triangle
According to Pythagoras theorem, AB² = XA² + BX²
∴ AB = √((40 × tan(55°))² + 5²) ≈ 57.34
The length of the tower, AB ≈ 57.34 m
