Answer :
Step-by-step explanation:
Given that,
The length of a ladder, H = 20 feet
The height of the wall, h = 15 ft
We know that,
[tex]\sin\theta=\dfrac{h}{H}[/tex]
h is perpendicular and H is hypotenuse
So,
[tex]\sin\theta=\dfrac{15}{20}\\\\\theta=\sin^{-1}(\dfrac{15}{20})\\\\\theta=48.59^{\circ}[/tex]
Now using Pythagoras theoerm,
[tex]b=\sqrt{H^2-h^2}\\\\b=\sqrt{20^2-15^2}\\\\b=13.2\ ft[/tex]
Hence, the angle made by the ladder and the ground is 48.59° and the ladder is 13.2 feet from the wall on the ground.