Dose anyone know how to solve this?

Answer:
Step-by-step explanation:
For 1: Multiply both functions together, expand, then simplify
(x-2)(3x²) = 3x³-6x²
For 2: Just add both functions together
For 3: Subtract both functions to get -3x²+x-2 and substitute x with -2
-3(-2)²-2-2 = -16
Answer:
[tex]f(x) = x - 2\\g(x) = 3x^2\\(f \cdot g)(x) = f(g(x))[/tex]
[tex]=f(3x^2) \\= (3x^2) - 2 \\= 3x^2 - 2[/tex]
[tex](f+g)(x) = f(x) + g(x)[/tex]
[tex]=(x-2) + (3x^2)\\= 3x^2 + x - 2[/tex]
[tex](f-g)(-2) = f(-2) - g(-2)[/tex]
[tex]= ((-2) - 2) - ( 3 (-2)^2)\\=(-2-2) - (3 \times 4)\\=-4-12\\=-16[/tex]