Answer:
[tex]adjacent = \sqrt{ {50}^{2} - {14}^{2} } = 48 \\ \\ \sin(Q) = \frac{14}{50} = \frac{7}{25} \\ \cos(Q) = \frac{48}{50} = \frac{24}{25} \\ \tan(Q) = \frac{14}{48} = \frac{7}{24} [/tex]
[tex] \sin(R) = \frac{48}{50} = \frac{24}{25} \\ \cos(R) = \frac{14}{50} = \frac{7}{25} \\ \tan(R) = \frac{48}{14} = \frac{24}{7} [/tex]
