does anyone know this?!

Answer:
2 is the numerical answer.
Explanation:
Hello there!
In this case, according to the given information and formula, it is possible for us to remember that equation for the calculation of the average kinetic energy of a gas is:
[tex]KE=\frac{3}{2} \frac{R}{N_A} T[/tex]
Whereas R is the universal gas constant, NA the Avogadro's number and T the temperature.
Which means that for the given ratio, we can obtain the value as follows:
[tex]=\frac{\frac{3}{2} \frac{R}{N_A} T_1}{\frac{3}{2} \frac{R}{N_A} T_2} \\\\=\frac{T_1}{T_2} \\\\=\frac{500K}{250K} \\\\=2[/tex]
Regards!