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[tex]12 {p}^{5} r \div ( - 10pq)[/tex]
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DEVISHRI1977GO

Answer:

Step-by-step explanation:

[tex]\frac{12p^{5}r}{-10pq} = \frac{-6p^{5-1}r}{5q}\\\\=\frac{-6p^{4}r}{5q}[/tex]

[tex]\frac{a^{m}}{a^{n}}=a^{m-n}[/tex]

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