Answered

A skier of weight 700 N is pointed down a ski hill that has a slope angle of 25° above horizontal.
What is the component of his weight pulling him down the slope.
O 634N
O 326N
O 296N
O 700N

Answer :

MACHMILLERGGO

Answer:

O 296N

Explanation:

F_y = F*sin(x)

F_y = 700N*sin(25°)

F_y = 295.83N or 296N

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