Answered

Fracisco's game involves 3 green, 2 yellow, 4 red, and 3 black marbles. If he randomly draws three marbles from the bag, without replacement, what is the probability that he will draw yellow, and then red, and then black?
StartFraction 1 over 192 EndFraction
StartFraction 1 over 72 EndFraction
StartFraction 3 over 220 EndFraction
StartFraction 1 over 55 EndFraction

Answer :

There are 13 marbles all together
Probability of drawing a yellow is 2/12
Don’t replace the marble
The probability of drawing a red marble is 4/11
Don’t put the marbles back in
The probability of drawing a black is 3/10
Multiply them together.
2/12 times 4/11 times 3/10.
24/1320 or. 1/55

Answer:

There are 12 marble if you add them all together, (3+2+4+3=12)

  • the probability of drawing a yellow is 2/12  
  • the probability of drawing a red marble is 4/11
  • The probability of drawing a black is 3/10

Multiply them together.

2/12 times 4/11 times 3/10.

=24/1320

Step-by-step explanation:

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