Answer:
[tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]
Explanation:
Hello there!
In this case, since redox reactions are characterized by the presence of a reduction reaction, whereby the oxidation of the element decreases, and an oxidation reaction whereby the oxidation of the element increases.
In such a way, for the given chemical equation, we can see Fe is increasing its oxidation state from 2+ to 3+, which means it is oxidized. On the flip side, Mn is being reduced from 7+ (MnO₄⁻) to 2+ and this, the reduction half-reaction is:
[tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]
Whereas five electrons are carried.
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