Answer:
0.2 m³/s
Step-by-step explanation:
Applying,
Q = vA.............. Equation 1
Where Q = Flow rate of air in the pipeline, v = flow velocity of the air in the pipeline, A = cross sectional area of the pneumatic pipeline.
From the question,
Given: v = 20 m/s, A = 0.01 m²
Substitute these values into equation 1
Q = 20(0.01)
Q = 0.2 m³/s
Hence the flow rate of air in the pipeline is 0.2 m³/s
