SOLAIMONH15GO
Answered

HELP DUE IN 15 MINS!

In rhombus ABCD, m∠CDE = 50°, DB = 12 ft, and AC = 16 ft

1. m∠CEB =?? degrees

2. m∠BCE =?? degrees

3. m∠ADE =?? degrees

4. ° DE =?? degrees

5. CB =?? degrees

HELP DUE IN 15 MINS In Rhombus ABCD MCDE 50 DB 12 Ft And AC 16 Ft 1 MCEB Degrees 2 MBCE Degrees 3 MADE Degrees 4 DE Degrees 5 CB Degrees class=

Answer :

Answer:

1.) m∠CEB = 90 degrees => The intersection is perpendicular

2.) m∠BCE = 40 degrees => 180 - (50 + 90)

3.) m∠ADE = 50 degrees => 180 - (40 + 90)

4.) DE = 6 ft => half of DB: 12/2

5.) CB = 10 ft => Using Pythagorean Theorem, solve:

                     =>  8² + 6² = CB²

                     =>  64 + 36 = CB²

                     =>  100 = CB²

                      => [tex]\sqrt{100}[/tex] = CB

                      => 10 = CB

Hope this helps!

JCHERRY99GO

Answer:

Step-by-step explanation:

I'm just adding the answer to 3. Give the other answerer the Brainliest.

Given a Rhombus, The diagonals bisect the angle that the diagonal is connect to

Therefore <ADE = 50 degrees, same as <CDE.

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