Answer :
Answer:
The probability that a candidate has less than 4 errors is 0.40
Step-by-step explanation:
Given
[tex]n(S)= 20[/tex] --- candidates
See attachment for histogram
Required
[tex]P(x < 4)[/tex]
From the attached histogram, the errors less than 4 are: 0 or 1 and 2 or 3
And the corresponding frequencies are: 5 and 3, respectively.
So:
[tex]P(x < 4) = P(0\ or\ 1) + P(2\ or\ 3)[/tex]
This gives:
[tex]P(x < 4) = \frac{n(0\ or\ 1)}{n(S)} + \frac{n(2\ or\ 3)}{n(S)}[/tex]
Substitute 5, 3 and 20 for n(0 or 1), n(2 or 3) and n(S), respectively
[tex]P(x < 4) = \frac{5}{20} + \frac{3}{20}[/tex]
Take LCM
[tex]P(x < 4) = \frac{5+3}{20}[/tex]
[tex]P(x < 4) = \frac{8}{20}[/tex]
[tex]P(x < 4) = 0.40[/tex]
