Answer:
[tex]m = 10\sqrt 3[/tex]
[tex]n = 10[/tex]
Step-by-step explanation:
Required
Find m and n
Considering the given angle, we have:
[tex]\sin(60) = \frac{Opposite}{Hypotenuse}[/tex]
This gives:
[tex]\sin(60) = \frac{m}{20}[/tex]
Make m ths subject
[tex]m = 20 * \sin(60)[/tex]
[tex]\sin(60) =\frac{\sqrt 3}{2}[/tex]
So, we have:
[tex]m = 20 *\frac{\sqrt 3}{2}[/tex]
[tex]m = 10\sqrt 3[/tex]
Considering the given angle again, we have:
[tex]\cos(60) = \frac{Adjacent}{Hypotenuse}[/tex]
This gives:
[tex]\cos(60) = \frac{n}{20}[/tex]
Make n the subject
[tex]n = 20 * \cos(60)[/tex]
[tex]\sin(60) =\frac{1}{2}[/tex]
So, we have:
[tex]n = 20 *\frac{1}{2}[/tex]
[tex]n = 10[/tex]
