Answer:
[tex](a)\ Area = 24in^2[/tex]
[tex](b)\ Area = 60in^2[/tex]
Step-by-step explanation:
Given
See attachment for the dimension of the block
Solving (a): Area of the front face
From the attachment, the front face has the following dimension.
[tex]Length = 4in[/tex]
[tex]Width = 6in[/tex]
The area is calculated as:
[tex]Area = Length *Width[/tex]
[tex]Area = 4in * 6in[/tex]
[tex]Area = 24in^2[/tex]
Solving (b): Area of the top and bottom faces
The top and bottom faces have the same dimension
From the attachment, the top face has the following dimension.
[tex]Length = 5in[/tex]
[tex]Width = 6in[/tex]
The area of the top is calculated as:
[tex]Area = Length *Width[/tex]
[tex]A_1 = 5in * 6in[/tex]
[tex]A_1 = 30in^2[/tex]
The area of the top and the bottom faces is:
[tex]Area = 2 *A_1[/tex] ---- because the top and bottom faces have the same dimension
[tex]Area = 2 *30in^2[/tex]
[tex]Area = 60in^2[/tex]
