The pOH of the solution is 10.4
The pH of the solution is 3.6
Calculating pOH & pH
From the question, we are to determine the pOH and pH of the solution
pOH can be calculated by using the formula
pOH = -log[OH⁻]
From the question,
[OH⁻] = 4×10⁻¹¹ M
∴ pOH = -log(4×10⁻¹¹)
pOH = 10.4
Hence, the pOH of the solution is 10.4
Now, for the pH
Using the formula,
pH + pOH = 14
Then, we can write that
pH = 14 - pOH
∴ pH of the solution is
pH = 14 - 10.4
pH = 3.6
Hence, the pH of the solution is 3.6
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