Answer:
P = 48 in²
Step-by-step explanation:
Given: A rectangle; Width = 9 inches, length = 15 inches, enlarged by a scale factor of [tex]\frac{3}{2}[/tex]
To find: Perimeter of the dilated rectangle
Formula: [tex]P=2(l+w)[/tex]
Solution: After a dilation with a scale factor of one-half, then the lengths on the image would be one-half , one-half , and one-half . To find the perimeter of an enlarged figure, you can multiply the original figure's perimeter by the scale factor.
[tex]P=2(l+w)=2[/tex] × [tex](15+9)=48in[/tex]
Therefore, the perimeter of the detailed rectangle that was enlarged is 48 in²
