Answer:
[tex]x=\sqrt{\dfrac{a(b-y^2)}{b}}[/tex]
Step-by-step explanation:
The given equation is :
[tex]x^2\div a+y^2\div b=1[/tex]
We need to find the value of x.
It can also written as :
[tex]\dfrac{x^2}{a}+\dfrac{y^2}{b}=1[/tex]
Subtract [tex]\dfrac{y^2}{b}[/tex] from both sides,
[tex]\dfrac{x^2}{a}+\dfrac{y^2}{b}-\dfrac{y^2}{b}=1-\dfrac{y^2}{b}\\\\\dfrac{x^2}{a}=\dfrac{b-y^2}{b}\\\\\text{Cross multiplying both sides}\\\\x^2=\dfrac{a(b-y^2)}{b}\\\\x=\sqrt{\dfrac{a(b-y^2)}{b}}[/tex]
Hence, the value of x is equal to [tex]\sqrt{\dfrac{a(b-y^2)}{b}}[/tex].
