Answer:
x approaches negative 3 to the right: [tex]lim_{x\to -3^{+}}=-\infty[/tex]
x approaches negative 3 to the left: [tex]lim_{x\to -3^{-}}=\infty[/tex]
Step-by-step explanation:
The function we have is:
[tex]f(x)=\frac{25x}{x+3}[/tex]
We have an asymptote at x = -3.
The limit of the function when x approaches negative 3 to the right will be:
[tex]lim_{x\to -3^{+}}=\frac{25x}{(-3)+3}=-\infty[/tex]
It is because the function is decreasing from right to left.
And the limit of the function when x approaches negative 3 to the left will be:
[tex]lim_{x\to -3^{-}}=\frac{25x}{(-3)+3}=\infty[/tex]
It is because the function is decreasing from left to right.
I hope it helps you!
