Answer:
[tex]\sf \dfrac{1}{21}[/tex]
Step-by-step explanation:
[tex]\textsf{To calculate}-\dfrac{2}{7}+\dfrac{1}{3}, \: \textsf{ first make the denominators the same}.[/tex]
[tex]\textsf{Adjust the fractions based on their lowest common multiplier}:[/tex]
[tex]\implies -\dfrac{2}{7} \cdot \dfrac{3}{3} + \dfrac{1}{3} \cdot \dfrac{7}{7}[/tex]
[tex]\implies -\dfrac{2 \cdot 3}{7 \cdot 3} + \dfrac{1 \cdot 7}{3 \cdot 7}[/tex]
[tex]\implies -\dfrac{6}{21}+\dfrac{7}{21}[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]
[tex]\implies \dfrac{-6+7}{21}[/tex]
[tex]\textsf{Add the numbers of the numerator}:[/tex]
[tex]\implies \dfrac{1}{21}[/tex]
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