Find the expected value of the winnings from a game that has the following payout probability distribution. Round to the nearest hundreath.

The expected value of the winnings from a game will be [tex]2.96[/tex] .
Probability is the ratio of the number of possible outcomes to the total number of outcomes.
we have,
Payout [tex](\$) = 0,\ \ \ 1,\ \ \ 2,\ \ \ 5,\ \ \ 10[/tex]
Probability [tex]=0.12,0.2,0.38,0.2,0.1[/tex]
So,
To find the expected value,
Now,
Multiply payout values with its probability and sum these values,
i.e.
Expected value [tex]= (0*0.12)+(1*0.2)+(2*0.38)+(5*0.2)+(10*0.1)[/tex]
[tex]=0+0.2+0.76+1+1[/tex]
Expected value [tex]=2.96[/tex]
Hence, we can say that the expected value of the winnings from a game will be [tex]2.96[/tex] .
To know more about Probability click here
https://brainly.com/question/27579447
#SPJ2