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You want to build a bicycle ramp that is 10 ft long and makes a 30 degree angle with the ground. What would be the height of the ramp?

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Answer :

CLARCH19GO

Answer:

5.8 feet

Step-by-step explanation:

this problem uses a 30-60-90° triangle

the ratio of sides in a 30-60-90° triangle, respectively, are 1 : [tex]\sqrt{3}[/tex] : 2

let 'h' = height of ramp

we can use this proportion, then cross-multiply:

10/h = [tex]\sqrt{3}[/tex]/1

[tex]\sqrt{3}[/tex]h = 10

h = 10/[tex]\sqrt{3}[/tex]

after rationalizing the denominator we get:

(10[tex]\sqrt{3}[/tex] ) ÷ 3 which is approximately 5.8 feet

ASHISHDWIVEDILVTGO

Using the trigonometric ratio, the height of the ramp is 5.77 feet.

Length of bicycle ramp = 10 feet

Angle with the ground = 30°

What is the sine of an angle?

The tangent of an angle is the ratio of the opposite side to the adjacent of the triangle.

Suppose the height of the ramp is h.

So, [tex]tan30=\frac{h}{10}[/tex]

[tex]h=10tan30[/tex]

[tex]h=\frac{10}{\sqrt{3} }[/tex]

[tex]h=5.77[/tex] feet.

So,  the height of the ramp is 5.77 feet.

Hence, using the trigonometric ratio, the height of the ramp is 5.77 feet.

To get more about the trigonometric ratios visit:

https://brainly.com/question/24349828

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