The element is Beryllium
Since the element tries to loose 2 electrons, the outer most shell must contain 2 electrons so that loosing it can satisfy its octet configuration.
We can then infer that the element has 4 electrons in its neutral state.,
Remember that,
No of electrons = Number of protons ( in a neutral atom.)
So the number of protons of this element is 4,
Recall also that
Proton number = Atomic number = 4
We can conclude that The element with atomic number of 4 is Beryllium with Electron Configuration, 1s2 2s2 and condensed form as [He]2s2.
Beryllium is also known for its exclusive +2 oxidation state in all its compounds.
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