On a coordinate plane, a curve goes through (negative 4, 8), curves down through (negative 2, 0), and approaches x = negative 1 in quadrant 3. Another curve approaches x = negative 1 in quadrant 2, has vertex (0, 0), and curves up through (2, 8). Another curve approaches x = 3 in quadrant 4 and curves up through (4, 16).
What are the one-sided limits of g(x) around the vertical asymptote x = –1?
Limit of g (x) as x approaches negative 1 minus = infinity and limit of g (x) as x approaches negative 1 plus = infinity
Limit of g (x) as x approaches negative 1 minus = infinity and limit of g (x) as x approaches negative 1 plus = negative infinity
Limit of g (x) as x approaches negative 1 minus = negative infinity and limit of g (x) as x approaches negative 1 plus = infinity
Limit of g (x) as x approaches negative 1 minus = negative infinity and limit of g (x) as x approaches negative 1 plus = negative infinity
