graph the equation y = -x^2 + 10x - 16 on the accompanying sex of axes. you must plot 5 points including the roots and the vertex

Answer :

Answer:

This is what I got! Hope it helps! :)

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The zeroes are (2, 0) and (8, 0),Vertex is (5, 9), remaining points plotted on the graph are (4,8) and (6,8).

What is graph of quadratic equation?

The graph is not a line. This figure is called a parabola. Every quadratic equation has a graph that looks like this.

All parabolas of the form y = [tex]a{x}^{2}+bx+c[/tex] open upwards or downwards.

When the [tex]{x}^{2}[/tex] term is positive, the parabola opens upward, and when the [tex]{x}^{2}[/tex] term is negative, the parabola opens downward.

After plotting the equation [tex]y=-x^{2} +10x-16[/tex]

From the graph i have labelled 5 points, they are

As per the graph the zeroes are (2, 0) and (8, 0),Vertex is (5, 9), remaining points plotted on the graph are (4,8) and (6,8).

Find out more information about graphing a quadratic equation here

https://brainly.com/question/14879503

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