Find the value of k so that the
line passing through the points
(k, -1) and (-2, 8) is parallel to
the equation 3x + y = -7.


Answer :

Answer:

[tex]gradient = - 3 \\ - 3 = \frac{(8 + 1)}{( - 2 - k)} \\ 3(2 + k) = 9 \\ 2 + k = 3 \\ k = 1[/tex]